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HPLinpack 1.0a  --  High-Performance Linpack benchmark  --   January 20, 2004
Written by A. Petitet and R. Clint Whaley,  Innovative Computing Labs.,  UTK
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An explanation of the input/output parameters follows:
T/V    : Wall time / encoded variant.
N      : The order of the coefficient matrix A.
NB     : The partitioning blocking factor.
P      : The number of process rows.
Q      : The number of process columns.
Time   : Time in seconds to solve the linear system.
Gflops : Rate of execution for solving the linear system.

The following parameter values will be used:

N      :   12000 
NB     :      60 
PMAP   : Row-major process mapping
P      :       3 
Q      :       3 
PFACT  :   Crout 
NBMIN  :       8 
NDIV   :       2 
RFACT  :   Right 
BCAST  :  BlongM 
DEPTH  :       0        1 
SWAP   : Mix (threshold = 60)
L1     : transposed form
U      : transposed form
EQUIL  : yes
ALIGN  : 8 double precision words

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- The matrix A is randomly generated for each test.
- The following scaled residual checks will be computed:
   1) ||Ax-b||_oo / ( eps * ||A||_1  * N        )
   2) ||Ax-b||_oo / ( eps * ||A||_1  * ||x||_1  )
   3) ||Ax-b||_oo / ( eps * ||A||_oo * ||x||_oo )
- The relative machine precision (eps) is taken to be          1.110223e-16
- Computational tests pass if scaled residuals are less than           16.0

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T/V                N    NB     P     Q               Time             Gflops
----------------------------------------------------------------------------
WR05R2C8       12000    60     3     3             139.04          8.287e+00
----------------------------------------------------------------------------
||Ax-b||_oo / ( eps * ||A||_1  * N        ) =        0.0111995 ...... PASSED
||Ax-b||_oo / ( eps * ||A||_1  * ||x||_1  ) =        0.0218696 ...... PASSED
||Ax-b||_oo / ( eps * ||A||_oo * ||x||_oo ) =        0.0044124 ...... PASSED
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T/V                N    NB     P     Q               Time             Gflops
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WR15R2C8       12000    60     3     3             139.67          8.250e+00
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||Ax-b||_oo / ( eps * ||A||_1  * N        ) =        0.0117979 ...... PASSED
||Ax-b||_oo / ( eps * ||A||_1  * ||x||_1  ) =        0.0230381 ...... PASSED
||Ax-b||_oo / ( eps * ||A||_oo * ||x||_oo ) =        0.0046481 ...... PASSED
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Finished      2 tests with the following results:
              2 tests completed and passed residual checks,
              0 tests completed and failed residual checks,
              0 tests skipped because of illegal input values.
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End of Tests.
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